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Solve the rational equation $\frac{\sec\left(x\right)^{2x}}{\tan\left(x\right)}=\sec\left(x\right)\csc\left(x\right)$

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 Solution

 Formulas

 Videos

Proof why tan(x) = sin(x)/cos(x)

https://www.youtube.com/watch?v=MepxHME-LXw

Tutorial - Solving a rational Equation ex2, 1/x + x/2 = (x+4)/ 2x

https://www.youtube.com/watch?v=a49VWDDgsMk

Algebra 2 - Learn to solve a rational equation by multiplying by the LCD (15/x)+((9x-7)/(x+2))=9

https://www.youtube.com/watch?v=BMSmvkWcVTU

Tutorial - Solving a rational Equation ex10, x/(x^2-2) = -1/x

https://www.youtube.com/watch?v=-C7OpRt_MFU

Algebra 2 - solving a rational equation by multiplying by the LCD (x/2) ‐ ((2x‐3)/5) = 1

https://www.youtube.com/watch?v=5VjEh8m5zfM

Algebra 2 - Solve rational expressions by multiplying the LCD on both sides x/2x+7 = (x‐5/x‐1)

https://www.youtube.com/watch?v=h2VlRHZhIBg

 Function Plot

Plotting: $\frac{\sec\left(x\right)^{2x}}{\tan\left(x\right)}-\sec\left(x\right)\csc\left(x\right)$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Rational Equations

Rational or fractional equations are those equations that contain algebraic fractions, and where the variable or unknown appears in the denominator of at least one of those fractions.

 Used Formulas

See formulas (2)

 Related Topics