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Decompose $32$ in it's prime factors
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$\left(2^{5}\right)^{\left(x^2-5x-3\right)}=1$
Learn how to solve problems step by step online. Solve the exponential equation 32^(x^2-5x+-3)=1. Decompose 32 in it's prime factors. Simplify \left(2^{5}\right)^{\left(x^2-5x-3\right)} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 5 and n equals x^2-5x-3. We can take out the unknown from the exponent by applying logarithms in base 10 to both sides of the equation. Evaluating the logarithm of base 2 of 1.