Solve the differential equation $y^{''}+6y^{\prime}+13y=0$

Step-by-step Solution

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Final answer to the problem

$y=e^{-3x}\left(C_0\cos\left(2x\right)+C_1\sin\left(2x\right)\right)$
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Step-by-step Solution

How should I solve this problem?

  • Exact Differential Equation
  • Linear Differential Equation
  • Separable Differential Equation
  • Homogeneous Differential Equation
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Load more...
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1

Obtain the characteristic equation

$r^{2}+6r+13=0$

Learn how to solve differential equations problems step by step online.

$r^{2}+6r+13=0$

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Learn how to solve differential equations problems step by step online. Solve the differential equation y^''+6y^'13y=0. Obtain the characteristic equation. Find the solutions to the quadratic equation r^{2}+6r+13=0. Of the complex solutions, take only the positive solution (the one where the coefficient of i is greater than 0). Express the complex root (\frac{-6+4i}{2}) in the form r=a+bi where a and b are constants.

Final answer to the problem

$y=e^{-3x}\left(C_0\cos\left(2x\right)+C_1\sin\left(2x\right)\right)$

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Function Plot

Plotting: $y=e^{-3x}\left(C_0\cos\left(2x\right)+C_1\sin\left(2x\right)\right)$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

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