Find the derivative of $\frac{x^4-16}{x+2}$

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Final answer to the problem

$\frac{4x^{4}+8x^{3}-x^4+16}{\left(x+2\right)^2}$
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Step-by-step Solution

How should I solve this problem?

  • Find the derivative
  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
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Apply the quotient rule for differentiation, which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$

$\frac{\frac{d}{dx}\left(x^4-16\right)\left(x+2\right)-\left(x^4-16\right)\frac{d}{dx}\left(x+2\right)}{\left(x+2\right)^2}$

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$\frac{\frac{d}{dx}\left(x^4-16\right)\left(x+2\right)-\left(x^4-16\right)\frac{d}{dx}\left(x+2\right)}{\left(x+2\right)^2}$

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Learn how to solve differential calculus problems step by step online. Find the derivative of (x^4-16)/(x+2). Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. Simplify the product -(x^4-16). The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a sum of two or more functions is the sum of the derivatives of each function.

Final answer to the problem

$\frac{4x^{4}+8x^{3}-x^4+16}{\left(x+2\right)^2}$

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Plotting: $\frac{4x^{4}+8x^{3}-x^4+16}{\left(x+2\right)^2}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

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