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Solve the product $\left(5x+3y\right)\left(5x-3y\right)$

Step-by-step Solution

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Final answer to the problem

$5x\cdot 5x+5x\left(-3y\right)+3y5x+3y\left(-3y\right)$
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Step-by-step Solution

How should I solve this problem?

  • FOIL Method
  • Product of Binomials with Common Term
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
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We can multiply the polynomials $\left(5x+3y\right)\left(5x-3y\right)$ by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First ($F\times F$), Outer by Outer ($O\times O$), Inner by Inner ($I\times I$), Last by Last ($L\times L$)

$\begin{matrix}(F\times F)\:=\:(5x)(5x)\\(O\times O)\:=\:(5x)(-3y)\\(I\times I)\:=\:(3y)(5x)\\(L\times L)\:=\:(3y)(-3y)\end{matrix}$

Learn how to solve constant rule for differentiation problems step by step online.

$\begin{matrix}(F\times F)\:=\:(5x)(5x)\\(O\times O)\:=\:(5x)(-3y)\\(I\times I)\:=\:(3y)(5x)\\(L\times L)\:=\:(3y)(-3y)\end{matrix}$

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Learn how to solve constant rule for differentiation problems step by step online. Solve the product (5x+3y)(5x-3y). We can multiply the polynomials \left(5x+3y\right)\left(5x-3y\right) by using the FOIL method. The acronym F O I L stands for multiplying the terms in each bracket in the following order: First by First (F\times F), Outer by Outer (O\times O), Inner by Inner (I\times I), Last by Last (L\times L). Then, combine the four terms in a sum. Substitute the values of the products.

Final answer to the problem

$5x\cdot 5x+5x\left(-3y\right)+3y5x+3y\left(-3y\right)$

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Plotting: $5x\cdot 5x+5x\left(-3y\right)+3y5x+3y\left(-3y\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Constant Rule for Differentiation

The constant rule for differentiation says that the derivative for any constant $k$ is equal to zero.

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