Solve the trigonometric integral $\int\sin\left(x\right)^4\cos\left(x\right)^4dx$

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Final answer to the problem

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)^{5}}{8}-\frac{3}{32}x-\frac{15}{256}\sin\left(2x\right)+\frac{-5\cos\left(x\right)^{3}\sin\left(x\right)}{64}-\frac{1}{16}\cos\left(x\right)^{5}\sin\left(x\right)+\frac{9}{128}\sin\left(2x\right)+\frac{3\cos\left(x\right)^{3}\sin\left(x\right)}{32}+C_0$
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Step-by-step Solution

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  • Integrate by parts
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
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  • Integrate using basic integrals
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Apply the formula: $\int\sin\left(\theta \right)^n\cos\left(\theta \right)^mdx$$=\frac{-\sin\left(\theta \right)^{\left(n-1\right)}\cos\left(\theta \right)^{\left(m+1\right)}}{n+m}+\frac{n-1}{n+m}\int\sin\left(\theta \right)^{\left(n-2\right)}\cos\left(\theta \right)^mdx$, where $m=4$ and $n=4$

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)^{5}}{4+4}+\frac{4-1}{4+4}\int\sin\left(x\right)^{2}\cos\left(x\right)^4dx$

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$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)^{5}}{4+4}+\frac{4-1}{4+4}\int\sin\left(x\right)^{2}\cos\left(x\right)^4dx$

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Learn how to solve trigonometric integrals problems step by step online. Solve the trigonometric integral int(sin(x)^4cos(x)^4)dx. Apply the formula: \int\sin\left(\theta \right)^n\cos\left(\theta \right)^mdx=\frac{-\sin\left(\theta \right)^{\left(n-1\right)}\cos\left(\theta \right)^{\left(m+1\right)}}{n+m}+\frac{n-1}{n+m}\int\sin\left(\theta \right)^{\left(n-2\right)}\cos\left(\theta \right)^mdx, where m=4 and n=4. Simplify the expression. The integral \frac{3}{8}\int\sin\left(x\right)^{2}\cos\left(x\right)^4dx results in: \frac{3\cos\left(x\right)^{3}\sin\left(x\right)}{32}+\frac{9}{64}x+\frac{9}{128}\sin\left(2x\right)-\frac{1}{16}\cos\left(x\right)^{5}\sin\left(x\right)+\frac{-5\cos\left(x\right)^{3}\sin\left(x\right)}{64}-\frac{15}{64}\left(\frac{1}{2}x+\frac{1}{4}\sin\left(2x\right)\right). Gather the results of all integrals.

Final answer to the problem

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)^{5}}{8}-\frac{3}{32}x-\frac{15}{256}\sin\left(2x\right)+\frac{-5\cos\left(x\right)^{3}\sin\left(x\right)}{64}-\frac{1}{16}\cos\left(x\right)^{5}\sin\left(x\right)+\frac{9}{128}\sin\left(2x\right)+\frac{3\cos\left(x\right)^{3}\sin\left(x\right)}{32}+C_0$

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Function Plot

Plotting: $\frac{-\sin\left(x\right)^{3}\cos\left(x\right)^{5}}{8}-\frac{3}{32}x-\frac{15}{256}\sin\left(2x\right)+\frac{-5\cos\left(x\right)^{3}\sin\left(x\right)}{64}-\frac{1}{16}\cos\left(x\right)^{5}\sin\left(x\right)+\frac{9}{128}\sin\left(2x\right)+\frac{3\cos\left(x\right)^{3}\sin\left(x\right)}{32}+C_0$

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u
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w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Trigonometric Integrals

Integrals that contain trigonometric functions and their powers.

Used Formulas

See formulas (2)

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