Solve the trigonometric integral $\int\sin\left(x\right)^4dx$

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Final answer to the problem

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x+C_0$
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Apply the formula: $\int\sin\left(\theta \right)^ndx$$=\frac{-\sin\left(\theta \right)^{\left(n-1\right)}\cos\left(\theta \right)}{n}+\frac{n-1}{n}\int\sin\left(\theta \right)^{\left(n-2\right)}dx$, where $n=4$

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}+\frac{3}{4}\int\sin\left(x\right)^{2}dx$

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$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}+\frac{3}{4}\int\sin\left(x\right)^{2}dx$

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Learn how to solve problems step by step online. Solve the trigonometric integral int(sin(x)^4)dx. Apply the formula: \int\sin\left(\theta \right)^ndx=\frac{-\sin\left(\theta \right)^{\left(n-1\right)}\cos\left(\theta \right)}{n}+\frac{n-1}{n}\int\sin\left(\theta \right)^{\left(n-2\right)}dx, where n=4. Multiply the single term \frac{3}{4} by each term of the polynomial \left(\frac{1}{2}x-\frac{1}{4}\sin\left(2x\right)\right). The integral \frac{3}{4}\int\sin\left(x\right)^{2}dx results in: \frac{1}{2}\cdot \frac{3}{4}x-\frac{1}{4}\cdot \frac{3}{4}\sin\left(2x\right). Gather the results of all integrals.

Final answer to the problem

$\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x+C_0$

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Function Plot

Plotting: $\frac{-\sin\left(x\right)^{3}\cos\left(x\right)}{4}-\frac{3}{16}\sin\left(2x\right)+\frac{3}{8}x+C_0$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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