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# Find the derivative of $\left(\frac{40+x}{140}\right)^5$

## Step-by-step Solution

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### Videos

$\frac{5\left(40+x\right)^{4}}{140^5}$
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## Step-by-step Solution

Problem to solve:

$\frac{d}{dx}\left(\left(\frac{40+x}{140}\right)^5\right)$

Specify the solving method

1

The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$

$\frac{d}{dx}\left(\frac{\left(40+x\right)^5}{140^5}\right)$

Learn how to solve differential calculus problems step by step online.

$\frac{d}{dx}\left(\frac{\left(40+x\right)^5}{140^5}\right)$

Learn how to solve differential calculus problems step by step online. Find the derivative of ((40+x)/140)^5. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. The derivative of a function multiplied by a constant (\frac{1}{140^5}) is equal to the constant times the derivative of the function. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. The derivative of a sum of two or more functions is the sum of the derivatives of each function.

$\frac{5\left(40+x\right)^{4}}{140^5}$
SnapXam A2

### beta Got another answer? Verify it!

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$\frac{d}{dx}\left(\left(\frac{40+x}{140}\right)^5\right)$