Final Answer
$\frac{4}{3}l^2b^2k^2$
Step-by-step explanation
Problem to solve:
$2\frac{2}{3}\cdot k\cdot b\cdot l\cdot k\cdot b\cdot l$
1
Divide $2$ by $3$
$2\cdot \frac{2}{3}kblkbl$
2
When multiplying two powers that have the same base ($k$), you can add the exponents
$\frac{4}{3}l^2b^2k^2$
Final Answer
$\frac{4}{3}l^2b^2k^2$