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# Simplify the algebraic expression $etxt\left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right)$

## Step-by-step Solution

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### Videos

$2et^2xq\left(q-3\right)$
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## Step-by-step Solution

Problem to solve:

$e t\cdot x\cdot t\cdot\left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right)$

Specify the solving method

1

When multiplying two powers that have the same base ($t$), you can add the exponents

$et^2x\left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right)$

Learn how to solve multiply powers of same base problems step by step online.

$et^2x\left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right)$

Learn how to solve multiply powers of same base problems step by step online. Simplify the algebraic expression etxt((q-3)(q-4)+(q-3)(q+4)). When multiplying two powers that have the same base (t), you can add the exponents. Factor the polynomial \left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right) by it's GCF: q-3. Subtract the values 4 and -4. Multiply e times 2.

$2et^2xq\left(q-3\right)$
SnapXam A2

### beta Got another answer? Verify it!

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0
a
b
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g
m
n
u
v
w
x
y
z
.
(◻)
+
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×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

$e t\cdot x\cdot t\cdot\left(\left(q-3\right)\left(q-4\right)+\left(q-3\right)\left(q+4\right)\right)$