Final answer to the problem
Step-by-step Solution
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Multiply the single term $x\left(x-2\right)\left(x-3\right)$ by each term of the polynomial $\left(x-1\right)$
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$x\cdot x\left(x-2\right)\left(x-3\right)-x\left(x-2\right)\left(x-3\right)+6x\left(x-1\right)\left(x-2\right)+9x\left(x-1\right)+3x$
Learn how to solve differential calculus problems step by step online. Expand the expression x(x-1)(x-2)(x-3)+6x(x-1)(x-2)9x(x-1)3x. Multiply the single term x\left(x-2\right)\left(x-3\right) by each term of the polynomial \left(x-1\right). When multiplying two powers that have the same base (x), you can add the exponents. Multiply the single term x^2\left(x-3\right) by each term of the polynomial \left(x-2\right). When multiplying exponents with same base you can add the exponents: x\cdot x^2\left(x-3\right).