When multiplying exponents with same base you can add the exponents: $x\cdot x^{-161}$
$x^{-160}$
2
Applying the property of exponents, $\displaystyle a^{-n}=\frac{1}{a^n}$, where $n$ is a number
$\frac{1}{x^{160}}$
Final answer to the problem
$\frac{1}{x^{160}}$
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