Simplify the expression $\frac{\left(x^4-x^2+1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^4-1\right)^2}{\left(x^2-1\right)\left(x^2+1\right)}$

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$\frac{\left(x^4-x^2+1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^{2}+1\right)^2\left(x^{2}-1\right)^2}{\left(x^2-1\right)\left(x^2+1\right)}$

Learn how to solve polynomial long division problems step by step online. Simplify the expression ((x^4-x^2+1)(x^2+x+1)(x^2-x+1)(x^4-1)^2)/((x^2-1)(x^2+1)). Factor the difference of squares \left(x^4-1\right) as the product of two conjugated binomials. Simplify the fraction \frac{\left(x^4-x^2+1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^{2}+1\right)^2\left(x^{2}-1\right)^2}{\left(x^2-1\right)\left(x^2+1\right)} by x^2-1. Simplify the fraction \frac{\left(x^4-x^2+1\right)\left(x^2+x+1\right)\left(x^2-x+1\right)\left(x^{2}+1\right)^2\left(x^2-1\right)}{x^2+1} by x^2+1. Solve the product of difference of squares .