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Expand the integral $\int\left(x^2+\frac{-x^2+1}{\sqrt[3]{x^3-3x+16}}\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int x^2dx+\int\frac{-x^2+1}{\sqrt[3]{x^3-3x+16}}dx$
Learn how to solve integrals of polynomial functions problems step by step online. Integrate int(x^2-(x^2-1)/((x^3-3x+16)^1/3))dx. Expand the integral \int\left(x^2+\frac{-x^2+1}{\sqrt[3]{x^3-3x+16}}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int x^2dx results in: \frac{x^{3}}{3}. The integral \int\frac{-x^2+1}{\sqrt[3]{x^3-3x+16}}dx results in: -\frac{1}{2}\sqrt[3]{\left(x^3-3x+16\right)^{2}}. Gather the results of all integrals.