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# Find the derivative of (x^2)/(2x-1)

### Videos

$\frac{2x\left(2x-1\right)-2x^2}{\left(2x-1\right)^2}$

## Step-by-step explanation

Problem

$\frac{d}{dx}\left(\frac{x^2}{2x-1}\right)$
1

Applying the quotient rule which states that if $f(x)$ and $g(x)$ are functions and $h(x)$ is the function defined by ${\displaystyle h(x) = \frac{f(x)}{g(x)}}$, where ${g(x) \neq 0}$, then ${\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}$

$\frac{\left(2x-1\right)\frac{d}{dx}\left(x^2\right)-x^2\frac{d}{dx}\left(2x-1\right)}{\left(2x-1\right)^2}$

$\frac{2x\left(2x-1\right)-2x^2}{\left(2x-1\right)^2}$