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# Find the derivative of $2^{'1}\frac{8}{x^2+4}$

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##  Final answer to the problem

$\frac{2^{'1}\cdot -16x}{\left(x^2+4\right)^2}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Find the derivative using the definition
• Find the derivative using the product rule
• Find the derivative using the quotient rule
• Find the derivative using logarithmic differentiation
• Find the derivative
• Integrate by partial fractions
• Product of Binomials with Common Term
• FOIL Method
• Integrate by substitution
Can't find a method? Tell us so we can add it.
1

Multiply the fraction by the term

$\frac{d}{dx}\left(\frac{2^{'1}\cdot 8}{x^2+4}\right)$

Learn how to solve differential calculus problems step by step online.

$\frac{d}{dx}\left(\frac{2^{'1}\cdot 8}{x^2+4}\right)$

Learn how to solve differential calculus problems step by step online. Find the derivative of 8/(x^2+4)2^'1. Multiply the fraction by the term . Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The derivative of the constant function (2^{'1}\cdot 8) is equal to zero. x+0=x, where x is any expression.

##  Final answer to the problem

$\frac{2^{'1}\cdot -16x}{\left(x^2+4\right)^2}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.