Find the derivative of $2^{'1}\frac{8}{x^2+4}$

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$\frac{d}{dx}\left(\frac{8\cdot 2^{'1}}{x^2+4}\right)$

Learn how to solve differential calculus problems step by step online. Find the derivative of 8/(x^2+4)2^'1. Simplify the derivative by applying the properties of logarithms. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The derivative of the constant function (8\cdot 2^{'1}) is equal to zero. Any expression multiplied by 0 is equal to 0.