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Factor the difference of cubes: $a^3-b^3 = (a-b)(a^2+ab+b^2)$
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$f\left(x\right)=\frac{2x^3+3}{\left(x-\left(- -1\right)^{\frac{1}{3}}\right)\left(x^2+\left(- -1\right)^{\frac{1}{3}}x+\left(- -1\right)^{\frac{2}{3}}\right)}$
Learn how to solve algebraic expressions problems step by step online. Simplify the expression f(x)=(2x^3+3)/(x^3-1). Factor the difference of cubes: a^3-b^3 = (a-b)(a^2+ab+b^2). Multiply -1 times -1. Multiply -1 times -1. Multiply -1 times -1.