ðŸ‘‰ Try now NerdPal! Our new math app on iOS and Android

# Find the integral $\int-e^{-x}dx$

## Step-by-step Solution

Go!
Math mode
Text mode
Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Videos

$e^{-x}+C_0$
Got another answer? Verify it here!

##  Step-by-step Solution 

Specify the solving method

1

The integral of a function times a constant ($-1$) is equal to the constant times the integral of the function

$-\int e^{-x}dx$

Learn how to solve integrals of exponential functions problems step by step online.

$-\int e^{-x}dx$

Learn how to solve integrals of exponential functions problems step by step online. Find the integral int(-e^(-x))dx. The integral of a function times a constant (-1) is equal to the constant times the integral of the function. We can solve the integral \int e^{-x}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that -x it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part. Now, in order to rewrite dx in terms of du, we need to find the derivative of u. We need to calculate du, we can do that by deriving the equation above. Isolate dx in the previous equation.

$e^{-x}+C_0$

##  Explore different ways to solve this problem

SnapXam A2

Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

### Main Topic: Integrals of Exponential Functions

Those are integrals that involve exponential functions. Recall that an exponential function is a function of the form f(x)=a^x.

###  Join 500k+ students in problem solving.

##### Without automatic renewal.
Create an Account