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Solve the trigonometric equation $\frac{\cot\left(x\right)^2}{\csc\left(x\right)+1}=1$

Step-by-step Solution

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Final answer to the problem

$x=\frac{1}{6}\pi+2\pi n,\:x=\frac{5}{6}\pi+2\pi n\:,\:\:n\in\Z$
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Step-by-step Solution

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Applying the trigonometric identity: $\cot\left(\theta \right)^2 = \csc\left(\theta \right)^2-1$

$\frac{\csc\left(x\right)^2-1}{\csc\left(x\right)+1}=1$

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$\frac{\csc\left(x\right)^2-1}{\csc\left(x\right)+1}=1$

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Learn how to solve trigonometric equations problems step by step online. Solve the trigonometric equation (cot(x)^2)/(csc(x)+1)=1. Applying the trigonometric identity: \cot\left(\theta \right)^2 = \csc\left(\theta \right)^2-1. The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: \displaystyle\frac{a^2-b^2}{a+b}=a-b.. We need to isolate the dependent variable , we can do that by simultaneously subtracting -1 from both sides of the equation. Multiply -1 times -1.

Final answer to the problem

$x=\frac{1}{6}\pi+2\pi n,\:x=\frac{5}{6}\pi+2\pi n\:,\:\:n\in\Z$

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Function Plot

Plotting: $\frac{\cot\left(x\right)^2}{\csc\left(x\right)+1}-1$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Trigonometric Equations

A trigonometric equation is an equation in which one or more trigonometric ratios appear.

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