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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\ln\left(\frac{1}{x}\right)+\ln\left(2x^3\right)=5.087596$
Learn how to solve rational equations problems step by step online. Solve the equation ln(1/x)+ln(2x^3)=ln(486)-ln(3). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Simplify the logarithm \ln\left(\frac{1}{x}\right). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Simplify the fraction \frac{2x^3}{x} by x.