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# Derive the function tan(x+1) with respect to x

### Formulas

$\sec\left(1+x\right)^2\frac{d}{dx}\left(1+x\right)$

## Step-by-step explanation

Problem

$\frac{d}{dx}\left(\tan\left(x+1\right)\right)$
1

The derivative of the tangent of a function is equal to secant squared of that function times the derivative of that function, in other words, if ${f(x) = tan(x)}$, then ${f'(x) = sec^2(x)\cdot D_x(x)}$

$\sec\left(1+x\right)^2\frac{d}{dx}\left(1+x\right)$

$\sec\left(1+x\right)^2\frac{d}{dx}\left(1+x\right)$