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A binomial squared (sum) is equal to the square of the first term, plus the double product of the first by the second, plus the square of the second term. In other words: $(a+b)^2=a^2+2ab+b^2$
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$2x^2-3x\geq 2\left(x^2+6x+9\right)$
Learn how to solve inequalities problems step by step online. Solve the inequality 2x^2-3x>=2(x+3)^2. A binomial squared (sum) is equal to the square of the first term, plus the double product of the first by the second, plus the square of the second term. In other words: (a+b)^2=a^2+2ab+b^2. Multiply the single term 2 by each term of the polynomial \left(x^2+6x+9\right). Factor the polynomial 2x^2-3x by it's greatest common factor (GCF): x. Grouping terms.