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1-\frac{2u-3}{4}=\frac{2-5u}{3}-3u

Solve the equation 1-1(2u-3)/4=(2-5u)/3-3u

Answer

$-\left(\frac{2-5u}{3}-3u\right)+\frac{3-2u}{4}+1=0$

Step-by-step explanation

Problem

$1-\frac{2u-3}{4}=\frac{2-5u}{3}-3u$
1

Grouping terms

$-\left(\frac{2-5u}{3}-3u\right)-\frac{2u-3}{4}+1=0$

Unlock this step-by-step solution!

Answer

$-\left(\frac{2-5u}{3}-3u\right)+\frac{3-2u}{4}+1=0$

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