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The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments
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$\log \left(\left(x-3\right)\left(x+2\right)\right)=\log \left(4x\right)$
Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation log(x+-3)+log(x+2)=log(4*x). The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. Grouping all terms to the left side of the equation. Multiply the single term x+2 by each term of the polynomial \left(x-3\right).