$16x^2+8x-79=0$
$tanh^{-1}\frac{2}{3}$
$\frac{1}{3}\int\left(\frac{1}{\tan\left(x\right)}\right)dx$
$\int\sqrt{1+a}da$
$f\left(x\right)=\frac{1}{x^2\left(x+1\right)\left(x+2\right)^3}$
$\left(-1\right)\cdot\left(-2\right)\cdot\left(-60\right)$
$-4-5+1-1$
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