Final Answer
$\frac{k^2+2k+2}{2\left(3+2k\right)}$
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Step-by-step Solution
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1
When multiplying two powers that have the same base ($k+1$), you can add the exponents
$\frac{\left(k+1\right)^2+1}{2\left(2\left(k+1\right)+1\right)}$
Learn how to solve simplification of algebraic fractions problems step by step online.
$\frac{\left(k+1\right)^2+1}{2\left(2\left(k+1\right)+1\right)}$
Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression ((k+1)(k+1)+1)/(2(2(k+1)+1)). When multiplying two powers that have the same base (k+1), you can add the exponents. Expand. Divide 2+k^2+2k by 6+4k. Resulting polynomial.
Final Answer
$\frac{k^2+2k+2}{2\left(3+2k\right)}$