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Find the break even points of the polynomial $\frac{\left(k+1\right)\cdot \left(k+1\right)+1}{2\left(2\left(k+1\right)+1\right)}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{\left(k+1\right)\cdot \left(k+1\right)+1}{2\left(2\left(k+1\right)+1\right)}=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression ((k+1)(k+1)+1)/(2(2(k+1)+1)). Find the break even points of the polynomial \frac{\left(k+1\right)\cdot \left(k+1\right)+1}{2\left(2\left(k+1\right)+1\right)} by putting it in the form of an equation and then set it equal to zero. When multiplying two powers that have the same base (k+1), you can add the exponents. Multiply both sides of the equation by 2\left(2\left(k+1\right)+1\right). We need to isolate the dependent variable , we can do that by simultaneously subtracting 1 from both sides of the equation.