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Solve the exponential equation $z=xe^{2x}+ye^{-2x}$

Step-by-step Solution

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Final Answer

$y=\frac{z-xe^{2x}}{e^{-2x}}$
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Step-by-step Solution

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Rearrange the equation

$xe^{2x}+ye^{-2x}=z$

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$xe^{2x}+ye^{-2x}=z$

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Learn how to solve exponential equations problems step by step online. Solve the exponential equation z=xe^(2x)+ye^(-2x). Rearrange the equation. We need to isolate the dependent variable , we can do that by simultaneously subtracting xe^{2x} from both sides of the equation. Divide both sides of the equation by e^{-2x}.

Final Answer

$y=\frac{z-xe^{2x}}{e^{-2x}}$

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Function Plot

Plotting: $z-xe^{2x}-ye^{-2x}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Exponential Equations

Exponential equations are those where the unknown appears only in the exponents of powers of constant bases.

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