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# Integrate the function $x+3$ from $-2$ to $3$

## Step-by-step Solution

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e
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ln
log
log
lim
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θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Formulas

$15$
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##  Step-by-step Solution 

Problem to solve:

$\int_{-2}^{3}\left(x+3\right)dx$

Specify the solving method

1

Expand the integral $\int_{-2}^{3}\left(x+3\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int_{-2}^{3} xdx+\int_{-2}^{3}3dx$

Learn how to solve differential calculus problems step by step online.

$\int_{-2}^{3} xdx+\int_{-2}^{3}3dx$

Learn how to solve differential calculus problems step by step online. Integrate the function x+3 from -2 to 3. Expand the integral \int_{-2}^{3}\left(x+3\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-2}^{3} xdx results in: \frac{5}{2}. The integral \int_{-2}^{3}3dx results in: 15. Gather the results of all integrals.

$15$

$17.5$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve int(x+3)dx&-2&3 using partial fractionsSolve int(x+3)dx&-2&3 using basic integralsSolve int(x+3)dx&-2&3 using u-substitutionSolve int(x+3)dx&-2&3 using integration by partsSolve int(x+3)dx&-2&3 using trigonometric substitution

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Go!
1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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