Final answer to the problem
$-\frac{289}{24}+6\left(g-\frac{1}{12}\right)^2$
Got another answer? Verify it here!
Step-by-step Solution
Specify the solving method
1
Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($6$) to all terms
$6\left(g^2-\frac{1}{6}g-2\right)$
Learn how to solve polynomial factorization problems step by step online.
$6\left(g^2-\frac{1}{6}g-2\right)$
Learn how to solve polynomial factorization problems step by step online. Factor the expression 6g^2-g+-12. Use the complete the square method to factor the trinomial of the form ax^2+bx+c. Take common factor a (6) to all terms. Add and subtract \displaystyle\left(\frac{b}{2a}\right)^2. Factor the perfect square trinomial g^2+-\frac{1}{6}gg+\frac{1}{144}. Subtract the values -2 and -\frac{1}{144}.
Final answer to the problem
$-\frac{289}{24}+6\left(g-\frac{1}{12}\right)^2$