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Find the integral $\int\frac{e^x+e^{-x}}{2}dx$

Step-by-step Solution

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Final Answer

$\frac{1}{2}e^x-\frac{1}{2}e^{-x}+C_0$
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Step-by-step Solution

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1

Take the constant $\frac{1}{2}$ out of the integral

$\frac{1}{2}\int\left(e^x+e^{-x}\right)dx$

Learn how to solve integrals of exponential functions problems step by step online.

$\frac{1}{2}\int\left(e^x+e^{-x}\right)dx$

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Learn how to solve integrals of exponential functions problems step by step online. Find the integral int((e^x+e^(-x))/2)dx. Take the constant \frac{1}{2} out of the integral. Simplify the expression inside the integral. The integral \frac{1}{2}\int e^xdx results in: \frac{1}{2}e^x. The integral \frac{1}{2}\int e^{-x}dx results in: -\frac{1}{2}e^{-x}.

Final Answer

$\frac{1}{2}e^x-\frac{1}{2}e^{-x}+C_0$

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Function Plot

Plotting: $\frac{1}{2}e^x-\frac{1}{2}e^{-x}+C_0$

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Got a different answer? Verify it!

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Integrals of Exponential Functions

Those are integrals that involve exponential functions. Recall that an exponential function is a function of the form f(x)=a^x.

Used Formulas

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