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Solve the quadratic equation $\frac{1}{7}+y^2-\frac{2}{5}=\frac{7}{3}y$

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 Final answer to the problem

$y=\frac{7}{6}+\sqrt{2}i,\:y=\frac{7}{6}-\sqrt{2}i$
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 Step-by-step Solution 

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Group the terms of the equation by moving the terms that have the variable $y$ to the left side, and those that do not have it to the right side

$y^2- \left(\frac{7}{3}\right)y=- \frac{1}{7}- -\frac{2}{5}$

Learn how to solve quadratic equations problems step by step online.

$y^2- \left(\frac{7}{3}\right)y=- \frac{1}{7}- -\frac{2}{5}$

Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation 1/7+y^2-2/5=7/3y. Group the terms of the equation by moving the terms that have the variable y to the left side, and those that do not have it to the right side. Multiply the fraction and term in - \left(\frac{7}{3}\right)y. Multiply the fraction and term in - \frac{1}{7}. Multiply the fraction and term in - -\frac{2}{5}.

 Final answer to the problem

$y=\frac{7}{6}+\sqrt{2}i,\:y=\frac{7}{6}-\sqrt{2}i$

 Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

 Main Topic: Quadratic Equations

The quadratic equations (or second degree equations) are those equations where the greatest exponent to which the unknown is raised is the exponent 2.

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