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Solve the quadratic equation $\frac{1}{7}+y^2-\frac{2}{5}=\frac{7}{3}y$

Step-by-step Solution

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Final answer to the problem

$y=\frac{239}{98},\:y=-\frac{31}{294}$
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Step-by-step Solution

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  • Find the derivative using the definition
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1

Subtract the values $\frac{1}{7}$ and $-\frac{2}{5}$

$-\frac{9}{35}+y^2=\frac{7}{3}y$

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$-\frac{9}{35}+y^2=\frac{7}{3}y$

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Learn how to solve problems step by step online. Solve the quadratic equation 1/7+y^2+-2/5=7/3y. Subtract the values \frac{1}{7} and -\frac{2}{5}. Divide 7 by 3. Grouping all terms to the left side of the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-\frac{7}{3} and c=-\frac{9}{35}. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

Final answer to the problem

$y=\frac{239}{98},\:y=-\frac{31}{294}$

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Function Plot

Plotting: $\frac{1}{7}+y^2-\frac{2}{5}-\frac{7}{3}y$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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