Solved example of separable differential equation
Group the terms of the differential equation. Move the terms of the $y$ variable to the left side, and the terms of the $x$ variable to the right side of the equality
Integrate both sides of the differential equation, the left side with respect to $y$, and the right side with respect to $x$
Rewrite the expression $\frac{1}{y^2-4}$ inside the integral in factored form
Rewrite the fraction $\frac{1}{\left(y+2\right)\left(y-2\right)}$ in $2$ simpler fractions using partial fraction decomposition
Find the values for the unknown coefficients: $A, B$. The first step is to multiply both sides of the equation from the previous step by $\left(y+2\right)\left(y-2\right)$
Multiplying polynomials
Simplifying
Expand the polynomial
Assigning values to $y$ we obtain the following system of equations
Proceed to solve the system of linear equations
Rewrite as a coefficient matrix
Reducing the original matrix to a identity matrix using Gaussian Elimination
The integral of $\frac{1}{\left(y+2\right)\left(y-2\right)}$ in decomposed fraction equals
Expand the integral $\int\left(\frac{-1}{4\left(y+2\right)}+\frac{1}{4\left(y-2\right)}\right)dy$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
Take the constant $\frac{1}{4}$ out of the integral
Take the constant $\frac{1}{4}$ out of the integral
Apply the formula: $\int\frac{n}{x+b}dx$$=n\ln\left(x+b\right)+C$, where $b=2$, $x=y$ and $n=-1$
Apply the formula: $\int\frac{n}{x+b}dx$$=n\ln\left(x+b\right)+C$, where $b=-2$, $x=y$ and $n=1$
Solve the integral $\int\frac{1}{y^2-4}dy$ and replace the result in the differential equation
The integral of a constant is equal to the constant times the integral's variable
As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$
Solve the integral $\int1dx$ and replace the result in the differential equation
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