Final answer to the problem
$y^2-x^3+8=\frac{-3x^2}{2y}=0$
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Step-by-step Solution
Specify the solving method
1
Any expression multiplied by $0$ is equal to $0$
$y^2-x^3+8=0+\frac{-3x^2}{2y}=0$
2
$x+0=x$, where $x$ is any expression
$y^2-x^3+8=\frac{-3x^2}{2y}=0$
Final answer to the problem
$y^2-x^3+8=\frac{-3x^2}{2y}=0$