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$\int\left(y\left(1+\frac{-y}{40}\right)-10\right)dy$
Learn how to solve integral calculus problems step by step online. Find the integral of y(1+(-y)/40)-10. Find the integral. Solve the product y\left(1+\frac{-y}{40}\right). Expand the integral \int\left(y+\frac{-y^2}{40}-10\right)dy into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int ydy results in: \frac{1}{2}y^2.