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Find the derivative of $\left(1-\frac{9}{50}-\frac{1}{2}-\frac{1}{20}-\frac{3}{20}\right)y$ using the definition

Step-by-step Solution

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Final answer to the problem

$\frac{3}{25}$
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Step-by-step Solution

How should I solve this problem?

  • Find the derivative using the definition
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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1

Subtract the values $1$ and $-\frac{9}{50}$

$derivdef\left(\left(\frac{41}{50}-\frac{1}{2}-\frac{1}{20}-\frac{3}{20}\right)y\right)$

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$derivdef\left(\left(\frac{41}{50}-\frac{1}{2}-\frac{1}{20}-\frac{3}{20}\right)y\right)$

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Learn how to solve problems step by step online. Find the derivative of y(1-9/50+-1/2+-1/20+-3/20) using the definition. Subtract the values 1 and -\frac{9}{50}. Subtract the values \frac{41}{50} and -\frac{1}{2}. Subtract the values \frac{8}{25} and -\frac{1}{20}. Subtract the values \frac{27}{100} and -\frac{3}{20}.

Final answer to the problem

$\frac{3}{25}$

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Function Plot

Plotting: $\frac{3}{25}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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