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$\int\ln\left(\frac{e^{4x}-1}{e^{4x}+1}\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of y=ln((e^(4x)-1)/(e^(4x)+1)). Find the integral. The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator. Expand the integral \int\left(\ln\left(e^{4x}-1\right)-\ln\left(e^{4x}+1\right)\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int-\ln\left(e^{4x}+1\right)dx results in: -\left(\left(e^{4x}+1\right)\ln\left(e^{4x}+1\right)-e^{4x}-1\right).