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$\int\left(a+\frac{b}{x^2}\right)^3dx$
Learn how to solve problems step by step online. Find the integral of y=(a+b/(x^2))^3. Find the integral. The cube of a binomial (sum) is equal to the cube of the first term, plus three times the square of the first by the second, plus three times the first by the square of the second, plus the cube of the second term. In other words: (a+b)^3=a^3+3a^2b+3ab^2+b^3 = (a)^3+3(a)^2(\frac{b}{x^2})+3(a)(\frac{b}{x^2})^2+(\frac{b}{x^2})^3 =. Simplify the expression inside the integral. The integral \int a^3dx results in: a^3x.