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Find the break even points of the expression $x^5=\frac{2}{5}$

Step-by-step Solution

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Final answer to the problem

$x=0.8325532$
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Step-by-step Solution

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Removing the variable's exponent raising both sides of the equation to the power of $\frac{1}{5}$

$\left(x^5\right)^{\frac{1}{5}}=\left(\frac{2}{5}\right)^{\frac{1}{5}}$

Learn how to solve classify algebraic expressions problems step by step online.

$\left(x^5\right)^{\frac{1}{5}}=\left(\frac{2}{5}\right)^{\frac{1}{5}}$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^5=2/5. Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{5}. Divide 1 by 5. Simplify \sqrt[5]{x^5} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 5 and n equals \frac{1}{5}. Multiply 5 times \frac{1}{5}.

Final answer to the problem

$x=0.8325532$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve for xFind the rootsSolve by factoringSolve by completing the squareSolve by quadratic formula (general formula)Find the discriminant

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Function Plot

Plotting: $x^5-\frac{2}{5}$

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Answer Assistant

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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