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Factor the trinomial $x^2-8x+15$ finding two numbers that multiply to form $15$ and added form $-8$
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$\begin{matrix}\left(-3\right)\left(-5\right)=15\\ \left(-3\right)+\left(-5\right)=-8\end{matrix}$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2-8x+15=0. Factor the trinomial x^2-8x+15 finding two numbers that multiply to form 15 and added form -8. Thus. Break the equation in 2 factors and set each equal to zero, to obtain. Solve the equation (1).