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Moving the term $12$ to the other side of the inequation with opposite sign
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$x^2-7x\leq 0-12$
Learn how to solve problems step by step online. Solve the inequality x^2-7x+12<=0. Moving the term 12 to the other side of the inequation with opposite sign. Subtract the values 0 and -12. Factor the polynomial x^2-7x. Add and subtract \left(\frac{b}{2}\right)^2, replacing b by it's value -7. Now, we can factor x^2+-7x+\frac{49}{4} as a squared binomial of the form \left(x+\frac{b}{2}\right)^2.