Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Find break even points
- Solve for x
- Find the roots
- Solve by factoring
- Solve by completing the square
- Solve by quadratic formula (general formula)
- Find the discriminant
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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Find the break even points of the polynomial $x^2-18x+81$ by putting it in the form of an equation and then set it equal to zero
Learn how to solve classify algebraic expressions problems step by step online.
$x^2-18x+81=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2-18x+81. Find the break even points of the polynomial x^2-18x+81 by putting it in the form of an equation and then set it equal to zero. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=-18 and c=81. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).