Final answer to the problem
Step-by-step Solution
Specify the solving method
Find the break even points of the polynomial $x^2+4x+4$ by putting it in the form of an equation and then set it equal to zero
To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=1$, $b=4$ and $c=4$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
Simplifying
To obtain the two solutions, divide the equation in two equations, one when $\pm$ is positive ($+$), and another when $\pm$ is negative ($-$)
Subtract the values $0$ and $-4$
Subtract the values $0$ and $-4$
Divide $-4$ by $2$
Divide $-4$ by $2$
Combining all solutions, the $2$ solutions of the equation are
Typically, in break-even points calculation problems, only the positive solutions to the equation are considered