Final answer to the problem
Step-by-step Solution
Specify the solving method
A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: $(a-b)^2=a^2-2ab+b^2$
Combining like terms $x^2$ and $x^2$
Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side
Subtract the values $3$ and $-1$
Rewrite the equation
Use the complete the square method to factor the trinomial of the form $ax^2+bx+c$. Take common factor $a$ ($2$) to all terms
Add and subtract $\displaystyle\left(\frac{b}{2a}\right)^2$
Factor the perfect square trinomial $x^2+-xx+\frac{1}{4}$
Subtract the values $-1$ and $-\frac{1}{4}$
Multiply $-1$ times $\frac{1}{2}$
Divide both sides of the equation by $2$
Simplifying the quotients
Divide $0$ by $2$
We need to isolate the dependent variable , we can do that by simultaneously subtracting $-\frac{5}{4}$ from both sides of the equation
Removing the variable's exponent
Cancel exponents $2$ and $\frac{1}{2}$
We need to isolate the dependent variable , we can do that by simultaneously subtracting $-\frac{1}{2}$ from both sides of the equation
As in the equation we have the sign $\pm$, this produces two identical equations that differ in the sign of the term $\sqrt{\left(\frac{5}{4}\right)}$. We write and solve both equations, one taking the positive sign, and the other taking the negative sign
Combining all solutions, the $2$ solutions of the equation are