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\frac{d}{dx}\left(x^2 / \left(x + y\right)\right) = \frac{d}{dx}\left(y^2 + 6\right)

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Final Answer

$\frac{x\left(x+2y-xy^{\prime}\right)}{\left(x+y\right)^2}=2y\cdot y^{\prime}$

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Math interpretation of the question

$\frac{d}{dx}\left(\frac{x^2}{x+y}\right)=\frac{d}{dx}\left(y^2+6\right)$

Learn how to solve implicit differentiation problems step by step online.

$\frac{d}{dx}\left(\frac{x^2}{x+y}\right)=\frac{d}{dx}\left(y^2+6\right)$

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Learn how to solve implicit differentiation problems step by step online. \frac{d}{dx}\left(x^2 / \left(x + y\right)\right) = \frac{d}{dx}\left(y^2 + 6\right). Math interpretation of the question. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}. The derivative of a sum of two or more functions is the sum of the derivatives of each function.

Final Answer

$\frac{x\left(x+2y-xy^{\prime}\right)}{\left(x+y\right)^2}=2y\cdot y^{\prime}$

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Main Topic: Implicit Differentiation

Implicit differentiation makes use of the chain rule to differentiate implicitly defined functions. For differentiating an implicit function y(x), defined by an equation R(x, y) = 0, it is not generally possible to solve it explicitly for y(x) and then differentiate. Instead, one can differentiate R(x, y) with respect to x and y and then solve a linear equation in dy/dx for getting explicitly the derivative in terms of x and y.

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