Final answer to the problem
$-\frac{1}{3}m^{3}+2m^2n+\frac{4}{3}n^{3}+C_0$
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Step-by-step Solution
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1
Find the integral
$\int\left(m^2+4mn+4n^2\right)dn$
Learn how to solve integral calculus problems step by step online.
$\int\left(m^2+4mn+4n^2\right)dn$
Learn how to solve integral calculus problems step by step online. Integrate the function m^2+4mn4n^2. Find the integral. Expand the integral \int\left(m^2+4mn+4n^2\right)dn into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int m^2dn results in: \frac{m^{3}}{3}. The integral \int4mndn results in: 2m^2n-\frac{2}{3}m^{3}.
Final answer to the problem
$-\frac{1}{3}m^{3}+2m^2n+\frac{4}{3}n^{3}+C_0$