Final answer to the problem
Step-by-step Solution
Specify the solving method
Apply the product rule for differentiation: $(f\cdot g)'=f'\cdot g+f\cdot g'$
Learn how to solve problems step by step online.
$100\frac{d}{dx}\left(\left(2x^3-x\right)^{99}\right)\left(6x^2-1\right)+\left(2x^3-x\right)^{99}\left(100\frac{d}{dx}\left(6x^2-1\right)+\left(6x^2-1\right)\frac{d}{dx}\left(100\right)\right)$
Learn how to solve problems step by step online. Factor the expression 100(2x^3-x)^99(6x^2-1). Apply the product rule for differentiation: (f\cdot g)'=f'\cdot g+f\cdot g'. The derivative of the constant function (100) is equal to zero. Any expression multiplied by 0 is equal to 0. x+0=x, where x is any expression.