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$\int\left(x^3-7\right)\left(2x^2+3\right)dx$
Learn how to solve problems step by step online. Find the integral of f(x)=(x^3-7)(2x^2+3). Find the integral. Rewrite the integrand \left(x^3-7\right)\left(2x^2+3\right) in expanded form. Expand the integral \int\left(2x^{5}+3x^3-14x^2-21\right)dx into 4 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int2x^{5}dx results in: \frac{1}{3}x^{6}.