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Find the break even points of the polynomial $9x^2-6x+1$ by putting it in the form of an equation and then set it equal to zero
Learn how to solve classify algebraic expressions problems step by step online.
$9x^2-6x+1=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression 9x^2-6x+1. Find the break even points of the polynomial 9x^2-6x+1 by putting it in the form of an equation and then set it equal to zero. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=9, b=-6 and c=1. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).