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Divide $\frac{8\cdot \left(\frac{9}{9+9}\right)\cdot \left(9+1\right)\cdot 9\cdot \left(9+6\right)}{2\cdot 9}$

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 Solution

 Videos

Algebra 2 - When Complex numbers are equal to each other, 5x + 1 + (3 + 2y)i = 2x - 2 + (y - 6)i

https://www.youtube.com/watch?v=avJ0qL4VO6o

Algebra 2-using synthetic division to divide two polynomials with a remainder (x^3‐x^2+9x‐3)/(x‐2)

https://www.youtube.com/watch?v=qzTkg7iFAbU

Algebra 2 - Simplifying complex numbers rational expression (2-4i) / (1+3i)

https://www.youtube.com/watch?v=a6RL2vmmPOU

Pre-Calculus - Operations with functions f(x) = 2x -5 , g(x) = 2-x and f(x) = x^2+6 , g(x) root(1-x)

https://www.youtube.com/watch?v=rthRvbioYyU

Algebra 2 - How to divide complex numbers (-5-9i) / (9+8i)

https://www.youtube.com/watch?v=53PYZbX5nEA

Multiplying and dividing in scientific notation (example) | Pre-Algebra | Khan Academy

https://www.youtube.com/watch?v=497oIjqRPco

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

 Main Topic: Division of numbers

The terms involved in a division are called, D, the dividend and, d, the divisor. The result, c, is the quotient.

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